Submission #1800034


Source Code Expand

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <cstdio>
#include <functional>
#include <numeric>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <utility>
#include <sstream>
#include <complex>
#include <fstream>
#include <bitset>
#include <time.h>
#include <tuple>

using namespace std;

typedef long long ll;
typedef pair<ll, ll> P;
typedef vector<ll> V;
typedef complex<double> Point;

#define PI acos(-1.0)
#define EPS 1e-10
const ll INF = 1e12;
const ll MOD = 1e9 + 7;

#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define rep(i,N) for(int i=0;i<(N);i++)
#define ALL(s) (s).begin(),(s).end()
#define EQ(a,b) (abs((a)-(b))<EPS)
#define EQV(a,b) ( EQ((a).real(), (b).real()) && EQ((a).imag(), (b).imag()) )
#define fi first
#define se second
#define N_SIZE (1LL << 20)
#define NIL -1

ll sq(ll num) { return num*num; }
ll mod_pow(ll x, ll n) {
	if (n == 0)return 1;
	if (n == 1)return x%MOD;
	ll res = sq(mod_pow(x, n / 2));
	res %= MOD;
	if (n % 2 == 1) {
		res *= x;
		res %= MOD;
	}
	return res;
}
ll mod_add(ll a, ll b) { return (a + b) % MOD; }
ll mod_sub(ll a, ll b) { return (a - b + MOD) % MOD; }
ll mod_mul(ll a, ll b) { return a*b % MOD; }

//部分点
//int k, n;
//string v[1000], w[1000];
//vector<string> table = { "a","b","c","aa","ab","ac" ,"ba","bb","bc" ,"ca","cb","cc",
//"aaa","aab","aac" ,"aba","abb","abc" ,"aca","acb","acc",
//"baa","bab","bac" ,"bba","bbb","bbc" ,"bca","bcb","bcc",
//"caa","cab","cac" ,"cba","cbb","cbc" ,"cca","ccb","ccc" };
//
//vector<vector<string>> vs;
//
//void solve(int now, const vector<string> &vss) {
//	if (now == k) {
//		vs.push_back(vss);
//		return;
//	}
//	rep(i, table.size()) {
//		vector<string> res = vss;
//		res.push_back(table[i]);
//		solve(now + 1, res);
//	}
//}
//
//
//int main() {
//	cin >> k >> n;
//	rep(i, n)cin >> v[i] >> w[i];
//	vector<string> t;
//	solve(0, t);
//	rep(i, vs.size()) {
//		rep(j, n) {
//			string s;
//			rep(k, v[j].size())s += vs[i][v[j][k] - '1'];
//			if (s != w[j])break;
//			if (j == n - 1) {
//				rep(l, k) {
//					cout << vs[i][l] << endl;
//				}
//				return 0;
//			}
//		}
//	}
//}

int k, n;
string v[1000], w[1000];

vector<vector<int>> vvi;

void solve(int now, const vector<int> &vi) {
	if (now == k) {
		vvi.push_back(vi);
		return;
	}
	rep(i, 3) {
		vector<int> res = vi;
		res.push_back(i + 1);
		solve(now + 1, res);
	}
}

int main() {
	cin >> k >> n;
	rep(i, n)cin >> v[i] >> w[i];
	vector<int> t;
	solve(0, t);
	map<char, string> mis;
	//vvi.clear();
	//t.push_back(1);
	//t.push_back(2);
	//t.push_back(3);
	//vvi.push_back(t);
	rep(i, vvi.size()) {
		mis.clear();
		bool f = 1;
		rep(j, n) {
			int pos = 0;
			rep(k, v[j].size()) {
				int ww = vvi[i][v[j][k] - '1'];
				if (mis[v[j][k]].empty()) {
					if (w[j].size() - pos < ww) {
						f = 0;
						break;
					}
					mis[v[j][k]] = w[j].substr(pos, ww);
				}
				else {
					if (mis[v[j][k]] != w[j].substr(pos, ww))f = 0;
				}
				pos += ww;
				if (!f)break;
			}
			if (pos != w[j].size())f = 0;
			if (!f)break;
		}
		if (f) {
			rep(i, k)cout << mis['1' + i] << endl;
			return 0;
		}
	}
}

Submission Info

Submission Time
Task D - 語呂合わせ
User jimmy
Language C++14 (GCC 5.4.1)
Score 100
Code Size 3314 Byte
Status AC
Exec Time 21 ms
Memory 1852 KB

Judge Result

Set Name Sample Subtask1 Subtask2
Score / Max Score 0 / 0 40 / 40 60 / 60
Status
AC × 4
AC × 23
AC × 44
Set Name Test Cases
Sample sample-01.txt, sample-02.txt, sample-03.txt, sample-04.txt
Subtask1 sample-02.txt, sample-03.txt, sample-04.txt, subtask1-01.txt, subtask1-02.txt, subtask1-03.txt, subtask1-04.txt, subtask1-05.txt, subtask1-06.txt, subtask1-07.txt, subtask1-08.txt, subtask1-09.txt, subtask1-10.txt, subtask1-11.txt, subtask1-12.txt, subtask1-13.txt, subtask1-14.txt, subtask1-15.txt, subtask1-16.txt, subtask1-17.txt, subtask1-18.txt, subtask1-19.txt, subtask1-20.txt
Subtask2 sample-01.txt, sample-02.txt, sample-03.txt, sample-04.txt, subtask1-01.txt, subtask1-02.txt, subtask1-03.txt, subtask1-04.txt, subtask1-05.txt, subtask1-06.txt, subtask1-07.txt, subtask1-08.txt, subtask1-09.txt, subtask1-10.txt, subtask1-11.txt, subtask1-12.txt, subtask1-13.txt, subtask1-14.txt, subtask1-15.txt, subtask1-16.txt, subtask1-17.txt, subtask1-18.txt, subtask1-19.txt, subtask1-20.txt, subtask2-01.txt, subtask2-02.txt, subtask2-03.txt, subtask2-04.txt, subtask2-05.txt, subtask2-06.txt, subtask2-07.txt, subtask2-08.txt, subtask2-09.txt, subtask2-10.txt, subtask2-11.txt, subtask2-12.txt, subtask2-13.txt, subtask2-14.txt, subtask2-15.txt, subtask2-16.txt, subtask2-17.txt, subtask2-18.txt, subtask2-19.txt, subtask2-20.txt
Case Name Status Exec Time Memory
sample-01.txt AC 1 ms 256 KB
sample-02.txt AC 1 ms 256 KB
sample-03.txt AC 1 ms 256 KB
sample-04.txt AC 1 ms 256 KB
subtask1-01.txt AC 1 ms 256 KB
subtask1-02.txt AC 1 ms 256 KB
subtask1-03.txt AC 1 ms 256 KB
subtask1-04.txt AC 1 ms 256 KB
subtask1-05.txt AC 1 ms 256 KB
subtask1-06.txt AC 1 ms 256 KB
subtask1-07.txt AC 1 ms 256 KB
subtask1-08.txt AC 1 ms 256 KB
subtask1-09.txt AC 1 ms 256 KB
subtask1-10.txt AC 1 ms 256 KB
subtask1-11.txt AC 1 ms 256 KB
subtask1-12.txt AC 1 ms 256 KB
subtask1-13.txt AC 1 ms 256 KB
subtask1-14.txt AC 1 ms 256 KB
subtask1-15.txt AC 1 ms 256 KB
subtask1-16.txt AC 1 ms 256 KB
subtask1-17.txt AC 1 ms 256 KB
subtask1-18.txt AC 1 ms 256 KB
subtask1-19.txt AC 1 ms 256 KB
subtask1-20.txt AC 1 ms 256 KB
subtask2-01.txt AC 8 ms 1852 KB
subtask2-02.txt AC 7 ms 1852 KB
subtask2-03.txt AC 8 ms 1852 KB
subtask2-04.txt AC 13 ms 1852 KB
subtask2-05.txt AC 7 ms 1852 KB
subtask2-06.txt AC 6 ms 1852 KB
subtask2-07.txt AC 21 ms 1852 KB
subtask2-08.txt AC 8 ms 1852 KB
subtask2-09.txt AC 21 ms 1852 KB
subtask2-10.txt AC 17 ms 1852 KB
subtask2-11.txt AC 18 ms 1852 KB
subtask2-12.txt AC 11 ms 1852 KB
subtask2-13.txt AC 8 ms 1852 KB
subtask2-14.txt AC 12 ms 1852 KB
subtask2-15.txt AC 8 ms 1852 KB
subtask2-16.txt AC 17 ms 1852 KB
subtask2-17.txt AC 6 ms 1852 KB
subtask2-18.txt AC 16 ms 1852 KB
subtask2-19.txt AC 14 ms 1852 KB
subtask2-20.txt AC 14 ms 1852 KB